Sunday, January 17, 2010

Additional Mathematics Form 4 Module

Assalamualaikum. Hello everyone!

Additional Mathematics Form 4 Module that I have prepared is based on my knowledge and reference books. Hopefully, it can help  students to understand and be master in Additional Mathematics.

I found that this module is frequently downloaded by form 4 students I guess as additional mathematics is something new for them.

Unfortunately, there are some information missing in this module like shaded part and others, so the information missing have to be added manually.Those who would like to use this module for reference, they may download it.

Last but not least, I would like to thank my beloved and respected Additional Mathematics teacher , Sir Abdul Halim Bin Othman. He is the one who inspired me to come out with this module. Syukran jazilan ya ustaz habibi ! Thanks a zillion , sir !

Chapter 1- Functions
Chapter 2- Quadratic Equations
Chapter 3- Quadratic Functions
Chapter 4- Simultaneous Equations
Chapter 5- Indices and Logarithms
Chapter 6- Coordinate Geometry
Chapter 7- Statistics
Chapter 8- Circular Measure
Chapter 9- Differentiation
Chapter 10- Solution of Triangles
Chapter 11- Index Number
Answer Sheet


Bonus:
Form 5 : Chapter 9 - Motion Along A Straight Line
 

http://www.4shared.com/file/123872332/834cb3f3/CHAPTER_7-_STATISTICS.html



90 comments:

admin said...

Hmm.. In the next 3 years this subject will be thought in Malay so this module is helpless soon.
Haha..

jannah eunkyung said...

itz 0whKay..
nyway..syukran jazilan yup?
:)

admin said...

'Afwan

Ummi Azian said...

Assalamualaikum wm wb.

Syukran atas modul add math Form 4. Ummi menuggu madul Form 5 pulak.

Wasallam.

admin said...

Wa'alaikumussalam..
sori la saya x buat modul form 5 memandangkan PPSMI akan dimansuhkan tak lama lagi.
rasa x berbaloi buat la.
huhu..

CG AIN said...

Terima kasih, semoga Allah akan membalas jasa anda

admin said...

Sama-sama...insya ALLAH mudah-mudahan.hehe..

irah said...

Barakallahu fik

admin said...

Syukran ya ukhti...

jaitheking said...

Thanks a lot for the notes,and god bless you

Ahmad Kamil said...

Welcome my buddy. thanks.

diana said...

ade tak jawapan untuk semua exercise??

Ahmad Kamil said...

Harap maaf la! Jwapan x disediakan dlm bentuk softcopy utk dimuat turun sama.

luve pink said...

ada x jwpn add math form4??

Ahmad Kamil said...

sekali lagi harap maaf! jawapan dlm bentuk soft copy x ada.

Ahmad Kamil said...

lagi sekali sori. x de.
dlm versi soft copy x de.
dlm versi hard copy ada la.

jahirah said...

thank you untuk segalanya hanya allah je akan balas budi saudara

ja said...

assamualaikum, terima kasih atas usaha saudara membuat modul yang bagus ini moga Allah membalas usaha baik saudara insyallah.

arina mastura said...

syukran sbb anta tlg ana cri bhan yg berguna

Maryam said...

Assalamu'alaikum.
bleh tlg upload soalan percubaan pmr pendidikan islam 2010?jazaakAllah. wassalam

anon said...

kenapa tiada jawapan? boleh tolong upload jawapan hardcopy tu tak? apa2 pun, terima kasih.

Nurul said...

fuh2.. jumpe masa googling. just the right thing at the right time.. sangkut bab function sbb lupa silibus lama...trimas a lot V(^^,)

zety said...

hm.. actely sy msh tak phm sgt addmath nih . dah nak finalexam doy tktnyer...

Najwa Anati said...

thnx vry mch 4 ths modul...it help me a lot in add maths...hope u cn shre mre thngs wth us...syukran jazilan...

Naim said...

Thx kk.......give math example

anip said...

thats good for all.....tanq youu mr kamil..

Nur Khaleeda said...

thankyou so much, mr kamil. its very kind of u. helps a lot:)

sepol said...

terima kasih encik kamil membantu saya....
semoga encik kamil akan mendapat ganjaran pahala.
trimas!

wanamiera said...

oh..still confuse dlm add math la..

tgh prepare nak masuk form 4 tahun dpn!
pening sgt!!!

roslan said...

tq ahmad kamil...ilmu yg brguna utk disebar bersama..teruskan usaha capai cita2 murni..minat math sgt2 ? teruskan

Ahmad Kamil said...

terima kasih saudara roslan. semoga ia dapat dimanfaatkan ye. =)

azizul said...

salam.. terima kasih untuk module ni..
really help me doing add maths exercise

Ahmad Kamil said...

w'salam...azizul.
sama2. semoga modul ni dpt membantu utk lebih kuasai addmath. =)

shukur said...

bgus btol blog ni...pasal add math plak 2...
dpt tolong sye dlm perbaiki kelemahan add math sye..
thx3...

Ahmad Kamil said...

kpd saudara shukur,
ni blog bkn semata2 psl addmath je ye. hehe..
ia merangkumi byk aspek kehidupan.
yg ada psl addmath ni sbb saya ni 'pelajar fanatik' maths. haha..
alhamdulillah, moga ia dapat tolong anta dlm lebih kuasai addmath.
'afwan ya akhi =)

Siti Khadijah Md Said said...

Saya amik latihan yang ada kat sini ehh? Terima Kasih! :)

Ahmad Kamil said...

Ambil je. nak bagi dkt2 kawan x pun jual pun x pe. hehe..

Wan Abd Majid said...

saya akn cuba bljr dari sini

Roslina ahmad said...

Assalamualaikum , Syabas kerana mewujudkan blog seperti ini , pada usia yang masih muda. Anda telah telah membuat sesuatu yang sangat berfaedah. Semoga Allah murahkan rezeki. Izinkan cikgu add link pada blog cik gu juga ye.

addreana said...

sayer amek note kat sini erk...nk ajar budak2 tution :)...terima kasih...

Ahmad Kamil said...

Cikgu Roslina:
Wa'alaikumussalam. alhamdulillah...terima kasih banyak2 cikgu atas respon yg diberikan. Mmg dialu2kan utk kongsikan link ni atau even modul ni dgn org lain tanpa perlu minta izin. hehe..

Cikgu Addrena:
Yeah..silakan cikgu. mmg boleh ambil je. smoga modul ni mmbantu cikgu utk mengajar tuisyen tu =)

hafizi said...

terima kasih banyak2 nota nie banyak membantu saya

hafizi said...

tolong selesai kan masalah ini terima kasih

hafizi said...

if f(x) 4x+5,find the composite function f kuasa 2,hence,find f kuasa 2 (1/2)

naediah_pocoyo said...

askm.
sy nk tny.kenape chapter 11 form 4 ta bole nak download ea.?
thanks.

Ahmad Kamil said...

Kpd hafizi:

f squared (x)
=f[f(x)]
=f(4x+5)
=4(4x+5) +5
=16x + 25

hence, f square (1/2) = 16(1/2) + 25
= 33

Kalau dia suruh cari terus f squared (1/2) , boleh buat mcm ni.
= f[f(1/2)]
= f( 4(1/2) +5]
= f(7)
= 4(7) + 5
= 33

Ahmad Kamil said...

w'salam...harap maaf ye. sbb link utk chapter 11 tu terletak utk answer sheet. bleh try download lg skali.

shahirah said...

sy mint addmath.. tp krg fhm cm ner nk cri funtion.. sy lmh dlm function..

Ahmad Kamil said...

Teruskan berusaha saudari shahirah.
banyakkan berdoa ye =)

mansor abdullah said...

assalamualaikum cikgu. saya adalah guru tuisyen dan saya akan mengendalikan bengkel matematik . saya ada download nota cikgu, saya minta izin untuk gunakan dalam pengajaran saya jika diizinkan. wassalam.

mansor abdullah said...

assalamualaikum cikgu,
boleh cikgu bagi tahu saya apa software atau apa saja untuk membuat nota, module atau soalan matematik.saya tidaka ada pendidikan yang formal dalam matematik. saya hanya `explore the mathematical world` kemudian saya mula mengajar. sekian . wassalam

Ahmad Kamil said...

Wa'alaikumussalam,cikgu.

Pertama,saya bukan cikgu sebenarnya. saya masih pelajar di pusat asasi UIAM tahun pertama.

Kedua, mmg modul addmaths ni amat dialu2kan utk semua org download & share dgn org lain. x perlu minta izin apa2 pun.

Ketiga, saya cuma gunakan Microsoft Words utk wt modul ni. cuma kena guna formula2 tertentu utk create equation & simbol2 maths tertentu.

shahirah said...

given f:x- 4x + m, g :x - nx + 1 and fg:x-8x + 7. find the value of m and n.. camner nk wak ek??

Ahmad Kamil said...

Bila nampak soalan mcm ni, automatically kita kena tahu ni soalan melibatkan 'comparison method'.

Dia bagi f, g and fg.

First of all, we find fg from f and g given,

fg(x)= f(nx + 1)
= 4(nx + 1) + m
= 4nx + m + 4

It is given that fg(x)= 8x + 7

So compare both of them,

4n = 8 and m + 4 = 7
n = 2 , m = 3

ainnur assyeilla said...

thanx for the module..
its really help me..
thnx

saidatul said...

sy minat dlm math.....

Ahmad Kamil said...

Ainnur: Welcome my brilliant buddy! hopefully it help u in order to be master in add maths.

fatinsyaz0711 said...

salam... thnx
may Allah bless..
doakan fatinsyaz 4 SPM 2011

akmal said...

nak tanye...ade contoh2 soalan tak?

Ahmad Kamil said...

contoh soalan? kalau nak contoh soalan tu, boleh la search dalam google ke yahoo ke. hehe..

mimin said...

Salam,
akak amek notes awk tau..reference tuk aja tusyen, thnks ye

Ahmad Kamil said...

w'slm. ambil je. x perlu minta izin pun. hehe. welcome!

liza said...

tak ada nota form 5 ke?

shahirah said...

given the function f(x)=x+15/x+3, x xsma dgn -3..find the value of x in which it maps to it self

Ahmad Kamil said...

Kpd liza, harap maaf x ada nota form 5 melainkan chapter 9 sahaja.

Ahmad Kamil said...

A domain maps to itself means f(x)=x,
x +15/ x+ 3 = x
x + 15 = x2 + 3x
x2 + 2x - 15 = 0
(x + 5)(x - 3) =0
x = -5 , x = 3

shahirah said...

maaf yer.. tapi naper jwpn yg diberi tak samer dngan jwpn dlm bku..-x=9/7
sy cme tak fhm solan tu nk ap..

Ahmad Kamil said...

equation yg bg tu btul ka? f(x)= (x+15)/(x+3) ke x + 15/x+3

dia minta cari nilai x or lain kata domain/object yg maps onto itself or codomain/image tu sama dgn object. tu yg tulis f(x)=x.

shahirah said...

btul r 2 equation 2.. ye srh cri nilai x yang dipetakan kpd dirinya sndiri..

nabila amira said...

h:x=ax+b, where a and b are constant
h square:x=25x-12
camne plak nk cri erk?

Ahmad Kamil said...

h(x)= ax + b , h sqaure x = hh(x)

h[h(x)] = h(ax + b)
= a(ax + b) + b
= a2x + ab + b --------------- 1

given that hh(x) = 25x - 12 -------------- 2

Compare 1 and 2,
a2 = 25
a= 5, -5

5b+b = -12 -5b+b = -12
b= -2 b= 3

klau dia x britahu condition a tu must greater than zero or vise versa, tu la jawapannya.

nabila amira said...

umur saya 16 thn..saya merupakan pelajar program permata pintar..dalam program ini, kami perlu berusaha sendiri..insruktor hanya mengajar asas sahaja..boleh tak awak jadi mentor saya??saya perlu panggil awak pe??

Ahmad Kamil said...

huhh..jadi mentor? Rasa mcm x layak je. hehehe... anyway, boleh je panggil saya akhi kamil..klau x suka arab pggil la abg kamil. hu3..

Nabila Amira said...

pe yang tak layak nye..abg kn pandai..
it is given f:x=5x+4 and g:x=ax+b. find the values of a and b if
fg(-1)=-1 and fg(1)=39..
method dia yang subtitute uh en??tapi saya tak dapat...
jawapan nye a=4,b=3

shahirah said...

kpd nabila.. sye nktlg jwb solan awk.. abg kamil tlg semak yer btl ke tidak..

f(x)=5x+4
g(x)=ax+b
fg(-1)=1

f[a(-1)+b]+4=1
5[-a+b]+4=1
-5a+5b+4=1


fg(1)=39
f[g(1)]=39
5[a+b]+4=39
5a+5b+4=39

compare both of them

shahirah said...

f(x) = 5x+4
g(x) = ax+b

g(1) = a + b , g(-1) = -a + b

f[g(-1)] = f(-a+b)
= 5(-a+b) + 4
fg(-1) = -5a + 5b + 4

Given fg(-1) = -1,
-5a + 5b +4 = -1
-5a + 5b= -5 ---------------1

f[g(1)] = f(a +b)
= 5(a + b) +4
fg(1) = 5a + 5b + 4

Given fg(1) = 39,
5a + 5b + 4 = 39
5a + 5b = 35 ---------------2

1 + 2,
10b = 30
b = 3

Sub b=3 into 2,
5a + 5(3) = 20
a = 4

SHAZ said...

SLM,bang.....sy minat sangat addmath......sampai org nk belajar dgn sy.....kalu sy tak fhm blh sy tanya abang.......:)

SHAZ said...

bang salah hantar....blh sy tanya bang

nabila amira said...

shahirah,
saya ta faham la camne awak compare..

Ahmad Kamil said...

SHAZ & Shahirah ni orang yg sama ye?

nabila: haha..apa2 je la. nak jadi mentor pun jadi jelah. hu2..

nabila amira said...

yay!!at last abg sudi gak jd mentor saya..huhuhu
lepas nh boleh lah abg kamil bantu saya..heehee:)
exam add math saya ari uh, trok sgt...
lebih krg 5 soalan saya tak jawab..
kami belajar 3 chapter dlm 3 weeks...
sbb tu de yg tak dpt catch up..
saya nk add fb abg. boleh tak??!
jgn lupe approve tau..

shahirah said...

eh bkn lah..org yg brlainan tp mggunakan email yg sma sbb shaz 2 kakak sy...sori ye kalu ada pape mslah yg brlaku

shukur said...

best la n0tes ni..thx...XD

panglima melaka said...

harap de notes untuk form 5...... :)

Ahmad Kamil said...

Shukur: welcome!!
Panglima Melaka: Dulu mmg plan nak buat. tapi dah PPSMI akan dimansuhkan, jadi rasa malas arh nak buat. hehehe...

ida said...

Assalamualaikum... nota yang penuh dengan penerangan.. Kesemuanya sudah saya downloadkan... Terimakasih di atas usaha saudara menyediakan nota yang cukup lengkap ini.. Cikgu Abdul Halim bin Othman juga merupakan guru add maths saya sewaktu f.5 di SMDSA arau, tahun 1984... Jasanya tetap dikenang sepanjang masa...

Ahmad Kamil said...

Wa'alaikumussalam...
oh..sama2. oh..ye ke? hehe..

panglima melaka said...

harap ade yg utntuk f0m 5 punyew......
sy ni minat nan add mth.....
lagi p0n tw0n ni sy spm....
:)

Ahmad Kamil said...

Harap maaf. Saya x buat modul bagi form 5.
Namun, ada sahabat saya yang dalam usaha buat modul form 5 tu kalau x silap.
jadi tunggu ye.

Anonymous said...

terima kasih banyak di atas sharing modul. sangat membantu dalam pengajaran dan pembelajaran anak-anak. semuga diberkati Allah sentiasa dan lapang rezeki tuan. terus kan perkongsian ilmu yg berguna ini :)